Re: repository files

[Ruud Dozijn]

> Ruud Dozijn <address@hidden> writes:
>
> > I am looking for an easy way to determine the file names in the 
> repository:
> >
> > - I check out a project
> > - I cd to the project directory (containing the CVS subdirectory)
> > - is there a cvs subcommand that returns the names of the files in the
> > current directory that also exist in the repository?
>
> You probably want the 'cvs status -l' or 'cvs log -l -R' command.
>
> If you just wanted a list of files, the following commands may be useful
> to you:
>
>    cvs -q -n status -l | grep File: | sed 's/File: \(.*\)Status:.*/\1/'
> or
>    cvs -q -n log -l -N -h | grep '^Working file: ' | sed 's/Working file: 
> //'
>
> otherwise, you may get more information than you really wanted.

It is allmost what I meant. The cvs log version is no good because it give 
the names of the repository files. In the cvs status command, the 
subdirectory names are not included.

What I want to do is write a script that processes all the files that are in 
the repository. So I need the file names of those files relatively to the 
current directory. I want to get a list like

file_1
file_2
in/file3
in/file4
out/put

using cvs -Q -n status -R, further processing would be needed if it reports 
a file FILE that exists in several subdirectories.

I'm not sure this is possible using the cvs subcommands. I thought maybe it 
is easier to use the output of the status subcommand, take the 'Repository 
revision' line and remove from the file name the ,v and the part of the 
filename that is in CVS/Repository and CVS/Root.
What do you think?

Ruud

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