Re: Fix issue 4355 -- broken beam subdivision (issue 226700043 by address@hidden)

[Carl . D . Sorensen]

On 2015/04/25 11:54:01, benko.pal wrote:
> 2015-04-25 10:20 GMT+02:00  <mailto:address@hidden>:
> > Thank you for picking this up. It is certainly an improvement
already.
> >
> > However: In an example where 8 32th notes are subdivided by 16th
notes
> > ony the first and third subdivision should have two beams, the
second
> > one only one beam.
> >
> > Put differently: when there is following a total of an eighth note's
> > worth there should be only one beam, even when that total is itself
> > subdivided into two sixteenth notes. (Presumably that logic should
be
> > propagated to the situation of (nested shorter notes): when 16 64th
> > notes are subdivided by 32ths the divisions should should have the
> > following number of beams: 3-2-3-1-3-2-3.

> could you formulate this more generally?
> e.g. what to do with 12 32th notes?

> p

If we have a baseMoment of 1/16, the 12 32nd notes will occur in 6 pairs
with 3 beams.

The 1st and 2nd pairs will be joined with a double beam, as will the 3rd
and 4th, and the 5th and 6th.

The beam between the 2nd and 3rd pair will be a single beam, as will the
beam between the 4th and 5th.



https://codereview.appspot.com/226700043/