Beaming sixteenths sandwiched in a triplet

[Chris Canipe]

I'm struggling in my attempts at beaming two sixteenths in the middle of a triplet. Is this possible with automatic beaming, or must one result to beam counts?

I've attached an example showing my current output and my desired output; code follows:

\paper{ ragged-right=##t }
\relative c'' {
    \time 4/4
    \times 2/3 { c8 c16 c c8 }
    r4 r r
}

Thanks!

P.S. I'm using version 2.10.33.

Example.png
Description: PNG image