Re: Beam with breaks

[Thomas Morley]

2016-08-02 15:53 GMT+02:00 Andrew Bernard <address@hidden>:
> Hello All,
>
> How would one achieve a beam with a break in it, as per the attached score
> extract?
>
> I know how to do the left hand side beaming in the image, but not the right
> hand side. Is this even possible, or do you have to blank it out with a
> white box (ugly)?
>
> This is not a mistake - it is a New Complexity School notation that is very
> common.
>
> Andrew


Hi Andreew,

perhaps:

{
  b!32[
  \set stemLeftBeamCount = #2
  \set stemRightBeamCount = #1
  a'16
  \set stemLeftBeamCount = #0
  \times 2/3 {
        fes'8
        \set stemLeftBeamCount = #2
        \set stemRightBeamCount = #0
        f16
        g'32]~
  } g'16
}

HTH,
  Harm