Re: How to break continuous ottava bracket

[Karol Majewski]

Sometimes you want to have two independent bars in one line:

{
c'1 ^"example 1"
d'1 \bar "||"
\ottava #1 c''1 ^"example 2"
d''1 \ottava #0 \bar "||"
\ottava #1 c''1 ^"example 3"
d''1 \ottava #0 \bar "||"

}

And here continuous ottava bracket looks stupid, doesn't it?

Is there more elegant way to break it? spacer rest does the job, but this solution is a bit artificial.

--Karol

2017-07-25 16:06 GMT+02:00 Simon Albrecht <address@hidden>:

On 25.07.2017 16:00, Karol Majewski wrote:

Hi, how to break ottava bracket beteween bars? The following gives me one continuous bracket

\ottava #1 c'1 \ottava #0
\ottava #1 c'1 \ottava #0

The bracket is continuous because the ottavation is continuous – there is no moment when the \ottava #0 actually takes effect.
You could fake it with

\ottava #1 c'1*1/2 \ottava #0 s2
\ottava #1 c'1

– but why?

Best, Simon