Not quite sure of the output you want
here. Your 2 lines of your example aren't the same since the top line has
a piano dynamic on it and the lower line doesn't. Is the first quaver
supposed to have the sf immediately below it? If so, where do you expect
the p dynamic to be? If it's below the second quaver, all lily can try to
do is space the quavers to fit in the minimum length of your hairpin, which it
does.
-- Phil Holmes
----- Original Message -----
Sent: Wednesday, October 30, 2019 3:14 PM
Subject: Hairpin.minimum-length gives wrong output
This
minimal criminal seems to give wrong output. I want to make sure that
the hairpin lasts for exactly one quaver (1/8 note). The first line gives a
warning message that the hairpin is too short. The second line adjusts the
length of the hairpin but it's now too long.
To try it out you may need
to modify the number of notes depending on the paper size.
\version
"2.19.52"
\language "english"
{ <<
\new Staff { \time 2/4
\clef "treble" c''8 8 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4
4 4 4 4 4 4 4 4 4\break c''8 8 4 4 4 4 4 4 4 4 4 4 4 4
4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 } \new
Dynamics { s8\sf\> s8\p s4 | s2 2 2 2 2 2 2 2 2 2 2
2 \override Hairpin.minimum-length = #5
s8\sf\> s8\! s4 | s2 2 2 2 2 2 2 2 2 2
} >> }
Regards,
Peter mailto:address@hidden www.ptoye.com
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