[Qemu-devel] [6469] SCSI divide capacity by s->cluster_size (Rik van Riel)

[Anthony Liguori]

Revision: 6469
          http://svn.sv.gnu.org/viewvc/?view=rev&root=qemu&revision=6469
Author:   aliguori
Date:     2009-01-28 21:58:29 +0000 (Wed, 28 Jan 2009)

Log Message:
-----------
SCSI divide capacity by s->cluster_size (Rik van Riel)

Paul Brook pointed out that the number of sectors reported
by the SCSI read capacity commands needs to be divided by
s->cluster_size, because bdrv_get_geometry reports the number
of 512 byte sectors, while emulated CDROMs report 2048 byte
sectors back to the guest.

This has no consequences for emulated hard disks, which use
a cluster size of 1.

aliguori: fixed typo

Signed-off-by: Rik van Riel <address@hidden>
Signed-off-by: Anthony Liguori <address@hidden>

Modified Paths:
--------------
    trunk/hw/scsi-disk.c

Modified: trunk/hw/scsi-disk.c
===================================================================
--- trunk/hw/scsi-disk.c        2009-01-28 21:58:25 UTC (rev 6468)
+++ trunk/hw/scsi-disk.c        2009-01-28 21:58:29 UTC (rev 6469)
@@ -734,6 +734,7 @@
         /* The normal LEN field for this command is zero.  */
        memset(outbuf, 0, 8);
        bdrv_get_geometry(s->bdrv, &nb_sectors);
+        nb_sectors /= s->cluster_size;
         /* Returned value is the address of the last sector.  */
         if (nb_sectors) {
             nb_sectors--;
@@ -834,6 +835,7 @@
             DPRINTF("SAI READ CAPACITY(16)\n");
             memset(outbuf, 0, len);
             bdrv_get_geometry(s->bdrv, &nb_sectors);
+            nb_sectors /= s->cluster_size;
             /* Returned value is the address of the last sector.  */
             if (nb_sectors) {
                 nb_sectors--;