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| From: | Avi Kivity |
| Subject: | Re: [Qemu-devel] How does a system call work on QEMU? |
| Date: | Thu, 14 May 2009 20:48:53 +0300 |
| User-agent: | Thunderbird 2.0.0.21 (X11/20090320) |
grisu46 wrote:
No. Look at target-i386/translate.c, case 0x105 for syscall emulation. Eventually it ends up calling helper_syscall().Simplify? I am a newbie.
Sorry, you're on your own. I can give you pointers but it's up to you to follow them. If you're serious about understanding qemu you should be prepared a lot of time reading the source code and processor documentation.
-- I have a truly marvellous patch that fixes the bug which this signature is too narrow to contain.
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