[Qemu-devel] Fwd: trigger a gpio interrupt inside qemu

[she roy]

---------- Forwarded message ----------
From: she roy <address@hidden>
Date: 2013/8/28
Subject: Re: [Qemu-devel] trigger a gpio interrupt inside qemu
To: Max Filippov <address@hidden>

I tested   qemu_irq_pulse(gPl061->irq); the guest did not generate an interrupt. so I changed to 

qemu_set_irq(gPl061->irq, 1);

sleep(1);  

qemu_set_irq(gPl061->irq, 0); 

A lot of interrupts generated. Is it possible to generate just one interrupt?

Thanks.

2013/8/27 Max Filippov <address@hidden>

On Tue, Aug 27, 2013 at 3:55 PM, she roy <address@hidden> wrote:
> How to lower it? Thank you very much!
>

qemu_set_irq(gPl061->irq, 0);

Or you could try

void pl061_raise_irq()
{
   qemu_irq_pulse(gPl061->irq);

}

> 2013/8/27 Max Filippov <address@hidden>
>>
>> On Tue, Aug 27, 2013 at 3:36 PM, she roy <address@hidden> wrote:
>> > Is there somebody can help me to trigger a gpio interrupt inside qemu? I
>> > wrote a simple function to trigger a interrupt in pl061.c as follow:
>> > PL061State *gPl061;
>> > void pl061_raise_irq()
>> > {
>> >     qemu_set_irq(gPl061->irq, 1);
>> > }
>>
>> [...]
>>
>> > But when i call pl061_raise_irq inside qemu once, the guest run into an
>> > infinite loop. it prints:
>> > ...
>> > irq:[927012]receive the irq at -12002...
>> > irq:[927013]receive the irq at -12002...
>> > irq:[927014]receive the irq at -12002...
>> > irq:[927015]receive the irq at -12002...
>> > irq:[927016]receive the irq at -12002...
>> > irq:[927017]receive the irq at -12002...
>> > irq:[927018]receive the irq at -12002...
>> > ...
>> > can somebody tell me what's wrong?
>>
>> You have raised IRQ in your pl061_raise_irq(), but you haven't lowered it.
>>
>> --
>> Thanks.
>> -- Max
>
>

--
Thanks.
-- Max