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Re: [Qemu-devel] [PATCH] memory: make ram device read/write endian sensi


From: Paul Mackerras
Subject: Re: [Qemu-devel] [PATCH] memory: make ram device read/write endian sensitive
Date: Fri, 24 Feb 2017 10:36:15 +1100
User-agent: Mutt/1.5.24 (2015-08-30)

On Thu, Feb 23, 2017 at 03:29:53PM +0000, Peter Maydell wrote:
> On 23 February 2017 at 15:21, Paolo Bonzini <address@hidden> wrote:
> >
> >
> > On 23/02/2017 15:35, Peter Maydell wrote:
> >> On 23 February 2017 at 12:53, Paolo Bonzini <address@hidden> wrote:
> >>>
> >>>
> >>> On 23/02/2017 13:26, Peter Maydell wrote:
> >>>> On 23 February 2017 at 11:43, Paolo Bonzini <address@hidden> wrote:
> >>>>> On 23/02/2017 12:34, Peter Maydell wrote:
> >>>>>> We should probably update the doc comment to note that the
> >>>>>> pointer is to host-endianness memory (and that this is not
> >>>>>> like normal RAM which is target-endian)...
> >>>>>
> >>>>> I wouldn't call it host-endianness memory, and I disagree that normal
> >>>>> RAM is target-endian---in both cases it's just a bunch of bytes.
> >>>>>
> >>>>> However, the access done by the MemoryRegionOps callbacks needs to match
> >>>>> the endianness declared by the MemoryRegionOps themselves.
> >>>>
> >>>> Well, if the guest stores a bunch of integers to the memory, which
> >>>> way round do you see them when you look at the bunch of bytes?
> >>>
> >>> You see them in whatever endianness the guest used.
> >>
> >> I'm confused. I said "normal RAM and this ramdevice memory are
> >> different", and you seem to be saying they're the same. I don't
> >> think they are (in particular I think with a BE guest on an
> >> LE host they'll look different).
> >
> > No, they look entirely the same.  The only difference is that they go
> > through MemoryRegionOps instead of memcpy.
> 
> Then we have a different problem, because the thing this patch
> is claiming to fix is that the memory the device is backed by
> (from vfio) is little-endian and we're not accessing it right.
> 
> RAM of the usual sort is target-endian (by which I mean "when the guest
> does a write of 32-bits 0x12345678, and you look at the memory byte
> by byte then the order of bytes is either 0x12 0x34 0x56 0x78 if
> TARGET_LITTLE_ENDIAN or 0x78 0x56 0x34 0x12 if TARGET_BIG_ENDIAN").
> 
> AIUI what we want for this VFIO case is "when the guest does
> a 32-bit write of 0x12345678 then the bytes are 0x12 0x34 0x56 0x78
> regardless of whether TARGET_BIG_ENDIAN or not".

At least in the case of KVM and MMIO emulation (which is the case
here), run->mmio.data should be considered as a byte stream without
endianness, and what is needed is for QEMU to transfer data between
run->mmio.data and the device (or whatever is backing the MMIO region)
without any net byte swap.

So if QEMU is doing a 32-bit host-endian load from run->mmio.data
(for an MMIO store), then it needs to do a 32-bit host-endian store
into the device memory.  In other words, the RAM memory region needs
to be considered host endian to match run->mmio.data being considered
host endian.

Paul.



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