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bug#54625: Why do I need to specify `-o auto` for join's `-e` option to
From: |
Iago-lito |
Subject: |
bug#54625: Why do I need to specify `-o auto` for join's `-e` option to work? |
Date: |
Tue, 29 Mar 2022 10:07:08 +0200 |
User-agent: |
Mozilla/5.0 (X11; Linux x86_64; rv:91.0) Gecko/20100101 Thunderbird/91.7.0 |
Hello,
This is a follow-up to this (yet) unanswered post on SE U&L:
https://unix.stackexchange.com/q/696259/87656, which I'm cross-posting
here. Don't hesitate to fire if it's the wrong place.
With the following two simple files:
|a.txt|
|1 a 2 b 5 c |
|b.txt|
|2 x 4 y 5 z |
The following command does not behave like expected:
|$ join -a 1 -a 2 -e 0 a.txt b.txt 1 a 2 b x 4 y 5 c z |
I would expect the option |-e 0| to fill up missing values with zeroes.
However, the following does work:
|$ join -a 1 -a 2 -e 0 -o auto a.txt b.txt 1 a 0 2 b x 4 0 y 5 c z |
Reading documentation from |$ man join|, I see no connection between
|-o| and |-e| that would make the above behaviour meaningful. Instead, I
find it misleading that a useless |-o auto| needs to be inserted into my
command for |-e 0| to work..
Is there an explanation, to be clarified in the manpage? Or is it a bug?
(btw:
$ join (GNU coreutils) 9.0
Copyright (C) 2021 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later
<https://gnu.org/licenses/gpl.html>.
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
Written by Mike Haertel.
)
--
Iago-lito
- bug#54625: Why do I need to specify `-o auto` for join's `-e` option to work?,
Iago-lito <=