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[PATCH] doc: clarify that ls --sort=time is newest first
From: |
Pádraig Brady |
Subject: |
[PATCH] doc: clarify that ls --sort=time is newest first |
Date: |
Wed, 1 Apr 2015 02:00:10 +0100 |
* src/ls.c (usage): Add punctuation to avoid ambiguity in the
description of the --time option. Mention that both the -u
and --sort=time default order is newest first.
---
src/ls.c | 6 +++---
1 file changed, 3 insertions(+), 3 deletions(-)
diff --git a/src/ls.c b/src/ls.c
index e406689..b2d7aa7 100644
--- a/src/ls.c
+++ b/src/ls.c
@@ -4888,9 +4888,9 @@ Sort entries alphabetically if none of -cftuvSUX nor
--sort is specified.\n\
,\n\
time (-t), version (-v), extension (-X)\n\
--time=WORD with -l, show time as WORD instead of default\n\
- modification time: atime or access or use
(-u)\n\
+ modification time: atime or access or use
(-u);\n\
ctime or status (-c); also use specified time\n\
- as sort key if --sort=time\n\
+ as sort key if --sort=time (newest first)\n\
"), stdout);
fputs (_("\
--time-style=STYLE with -l, show times using style STYLE:\n\
@@ -4911,7 +4911,7 @@ Sort entries alphabetically if none of -cftuvSUX nor
--sort is specified.\n\
fputs (_("\
-u with -lt: sort by, and show, access time;\n\
with -l: show access time and sort by name;\n\
- otherwise: sort by access time\n\
+ otherwise: sort by access time, newest first\n\
-U do not sort; list entries in directory order\n\
-v natural sort of (version) numbers within text\n\
"), stdout);
--
2.1.0
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