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[PATCH] doc: clarify that ls --sort=time is newest first


From: Pádraig Brady
Subject: [PATCH] doc: clarify that ls --sort=time is newest first
Date: Wed, 1 Apr 2015 02:00:10 +0100

* src/ls.c (usage): Add punctuation to avoid ambiguity in the
description of the --time option.  Mention that both the -u
and --sort=time default order is newest first.
---
 src/ls.c | 6 +++---
 1 file changed, 3 insertions(+), 3 deletions(-)

diff --git a/src/ls.c b/src/ls.c
index e406689..b2d7aa7 100644
--- a/src/ls.c
+++ b/src/ls.c
@@ -4888,9 +4888,9 @@ Sort entries alphabetically if none of -cftuvSUX nor 
--sort is specified.\n\
 ,\n\
                                time (-t), version (-v), extension (-X)\n\
       --time=WORD            with -l, show time as WORD instead of default\n\
-                               modification time: atime or access or use 
(-u)\n\
+                               modification time: atime or access or use 
(-u);\n\
                                ctime or status (-c); also use specified time\n\
-                               as sort key if --sort=time\n\
+                               as sort key if --sort=time (newest first)\n\
 "), stdout);
       fputs (_("\
       --time-style=STYLE     with -l, show times using style STYLE:\n\
@@ -4911,7 +4911,7 @@ Sort entries alphabetically if none of -cftuvSUX nor 
--sort is specified.\n\
       fputs (_("\
   -u                         with -lt: sort by, and show, access time;\n\
                                with -l: show access time and sort by name;\n\
-                               otherwise: sort by access time\n\
+                               otherwise: sort by access time, newest first\n\
   -U                         do not sort; list entries in directory order\n\
   -v                         natural sort of (version) numbers within text\n\
 "), stdout);
-- 
2.1.0




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