Re: Expanding aliases to full command before execution

[dethrophes]

Am 04.04.2012 17:27, schrieb jrrandall@gmail.com:
> On Tue, Apr 3, 2012 at 5:22 PM, jrrandall@gmail.com<jrrandall@gmail.com>  wrote:
> > Hi everyone,
> >
> > In bash, is it possible to expand my aliases either before they are executed
> > or when they are stored in the history file?
> > For example, if I have:  alias ll='ls -l'  defined in my .bashrc, when I
> > execute "ll" from the command line, I'd like my history file to contain "ls
> > -l".  Is there any way to accomplish this?
> >
> > Thanks,
> > Justin
> I seem to have constructed a solution to my own problem.  I wrote a
> function that creates the desired behavior for me and saves it in
> $expanded if the argument was in fact an alias.
>
> function expand_alias()                 # expand an alias to full command
> {
>      if [ "$1" = "." ]; then
>          argument="\\$1"
>      else
>          argument="$1"
>      fi
>      match=$( alias -p | grep -w "alias $argument=" )
>      if [ -n "$match" ]; then
>          expanded="`echo $match | sed -e s/[^=]*=// | sed 's/^.\(.*\).$/\1/'`"
>      else
>          expanded="$1"
>      fi
> }
>
>
> Thanks,
> Justin
or you could just do

function expand_alias()                 # expand an alias to full command
{
    if expanded=$( alias "${1}" ); then
        expanded="${expanded#*=}"
    else
        expanded="$1"
    fi
}

though depending on what your actually trying to do you'd be getter of 
using type, as not all aliases are aliases a lot are functions these days.



    case $(type -t "$c") in
      "")
        echo No such command "$c"
        return 127
        ;;
      alias)
        c="$(type "$c"|sed "s/^.* to \`//;s/.$//")"
        ;;
      function)
        c=$(type "$c"|sed 1d)";\"$c\""
        ;;
      *)
        c="\"$c\""
        ;;
    esac

bash -xvc "$c"