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Re: status on $[arith] for eval arith vsl $((arith))??
From: |
Chet Ramey |
Subject: |
Re: status on $[arith] for eval arith vsl $((arith))?? |
Date: |
Sun, 08 Apr 2012 15:30:45 -0400 |
User-agent: |
Mozilla/5.0 (Macintosh; Intel Mac OS X 10.6; rv:10.0.2) Gecko/20120216 Thunderbird/10.0.2 |
On 4/8/12 3:02 PM, Maarten Billemont wrote:
> Any particular reason for not removing old undocumented functionality, or is
> that mostly the nature of this beast - dragging along and maintaining ancient
> code for the sake of compatibility?=
Because, as Linda discovered, there is still working code out there using
it. Maybe we'll get to a point where it's all gone, but we're not there
yet.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU chet@case.edu http://cnswww.cns.cwru.edu/~chet/
- status on $[arith] for eval arith vsl $((arith))??, Linda Walsh, 2012/04/07
- Re: status on $[arith] for eval arith vsl $((arith))??, Mike Frysinger, 2012/04/07
- Re: status on $[arith] for eval arith vsl $((arith))??, Chet Ramey, 2012/04/07
- Re: status on $[arith] for eval arith vsl $((arith))??, Maarten Billemont, 2012/04/08
- Re: status on $[arith] for eval arith vsl $((arith))??,
Chet Ramey <=
- Re: status on $[arith] for eval arith vsl $((arith))??, dethrophes, 2012/04/08
- Re: status on $[arith] for eval arith vsl $((arith))??, Maarten Billemont, 2012/04/09
- Re: status on $[arith] for eval arith vsl $((arith))??, Linda Walsh, 2012/04/09
- Re: status on $[arith] for eval arith vsl $((arith))??, Maarten Billemont, 2012/04/10
- Re: status on $[arith] for eval arith vsl $((arith))??, Chet Ramey, 2012/04/10
- Message not available
- Re: status on $[arith] for eval arith vsl $((arith))??, Aharon Robbins, 2012/04/09
- Re: status on $[arith] for eval arith vsl $((arith))??, Linda Walsh, 2012/04/09
- Re: status on $[arith] for eval arith vsl $((arith))??, Chet Ramey, 2012/04/09
- Re: status on $[arith] for eval arith vsl $((arith))??, Elliott Forney, 2012/04/10
- Re: status on $[arith] for eval arith vsl $((arith))??, Chet Ramey, 2012/04/10