Re: declare -ag with assignment bug

[Chet Ramey]

On 4/26/12 4:50 PM, Joseph Graham wrote:

> Bash Version: 4.2
> Patch Level: 24
> Release Status: release
> 
> Description:
> Arrays defined in a function with declare -ag are not
> available outside the function if an assignment is done with the
> declaration, though it works if the assignment is done seperately from
> the declaration.
> 
> Repeat-By:
> $ f() { declare -ag a=(my array); }; f; declare -p a
> declare -a a='()'
> $ f() { declare -ag a; a=(my array); }; f; declare -p a
> declare -a a='([0]="my" [1]="array")'

http://lists.gnu.org/archive/html/help-bash/2012-04/msg00000.html

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    chet@case.edu    http://cnswww.cns.cwru.edu/~chet/