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From: | Glenn Golden |
Subject: | bug#49381: v.8.32 – du(1) | Calculating the total size of files | One file covered instead of all |
Date: | Sun, 4 Jul 2021 08:35:12 -0600 |
User-agent: | Mutt/1.10.1 (2018-07-13) |
Ricky Tigg <ricky.tigg@gmail.com> [2021-07-04 16:54:04 +0300]: > *OS:* Fedora; Tested in Bash v.5.1. > > Hello. Task: Printing total size of files *alone*. > To reproduce: > > $ stat -c '%i %h %s %n %F' k l > 4198568 2 34 k regular file > 4198568 2 34 l regular file > > $ find . -type f > ./k > ./l > > Those 'du' commands cover only one file instead of all files. > > $ find . -type f -exec du -acb {} + > 34 ./k > 34 total > > $ find . -type f -print0 | du --files0-from=- -cb > 34 ./k > 34 total > > Isn't rather *68* expected? You probably want to specify --count-links if you want hardlinked files (like your example k and l) to be considered by du as separate files: $ echo foo > k $ ln k l $ du -c k l 4 k 4 total $ du -c --count-links k l 4 k 4 l 8 total
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