How to add a non-fixed number of 0s?

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Hi,

I want to add a certain number of 0s to the input, but I don??t know the specific number of 0s. I wrote a python block to complete this work, but I don??t seem to understand how the Python block works, which causes it to not work properly. code show as below:

class...

        self.k = k

        self.total = 0

    def work(self, input_items, output_items):

        in0 = input_items[0]

        out = output_items[0]

        in0_len = len(in0)

        self.total = self.total + in0_len

        i = 0

        while i<in0_len:

            out[i] = in0[i]

            i=i+1

        if in0_len < len(output_items[0]):#I found that this sentence does not work. My previous understanding is that each "input_items" and "output_items" has a fixed value (4096). I need to determine that the input item has ended, and then enter the following operation

            remainder1 = self.total % self.k

            if remainder1 != 0:

                while True:

                    out = np.append(out, 0)

                    self.total =self.total+1

                    remainder2 = self.total % self.k

                    i = i+1

                    if i==len(output_items[0]) or remainder2==0:

                        break

        return len(output_items[0])

I think my problem is that this is a synchronized block, the number of input and output is the same, so it is never possible to enter the "if" statement, but I don't know what mechanism should I use to make the number of input and output inconsistent, "interpolation block "The output is a multiple of the input, and it cannot be used by me. How can I solve this problem, thank you in advance??

Best Regards,

linge93