Re: Can Bash do simple math?

[alex xmb sw ratchev]

On Tue, Aug 6, 2024, 00:34 <bash@blaklinten.xyz> wrote:

> I have a somewhat strange issue.
> In a script I use the `((VAR = expression ))` syntax to calculate a
> simple remainder by division:
>
>   ((DIFF = $2 - $1))
>   ((SECONDS = DIFF % 60))
>   ((MINUTES = (DIFF % 3600) / 60))
>   ((HOURS = DIFF / 3600))
>

just .. what u do diff % 60 , 'SECONDS' it is already .. % 60 ( if it
counts as how many 60thiet times ) is minutes already
i suppose u mean $2(seconds) -1(seconds) , = seconds
if thats not ur case plz explain

  echo "$HOURS:$MINUTES:$SECONDS"
>
> However, it seems as if Bash sometimes miscalculates the remainder and
> prints an errorneous result string.
>
> I have written a small example and had some friends run it to confirm
> this issue is not only on my machine.
> I highly doubt Bash _sometimes_ miscalculates basic math and neither
> me or my friends can spot any errors in my code. Am I stupid? What am
> I missing?
>
> The minimal example code to produce an error:
> https://gist.github.com/blaklinten/3dd29f3f73b75337a86b8d7cdb59bdd7
>
> I am eager to hear thoughts on this :)
>
>