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Re: Why does case-pattern undergo "process substitution"?
From: |
Eric Pruitt |
Subject: |
Re: Why does case-pattern undergo "process substitution"? |
Date: |
Fri, 23 Aug 2024 14:39:24 -0700 |
On Fri, Aug 23, 2024 at 07:47:43PM +0000, shynur . wrote:
> I'm confused. Why is "process substitution" being performed here?
> The result is often unforeseen, e.g., '/dev/fd/13', '/dev/fd/42'...
> Can anyone give me a practical example? Thanks in advance!
Hopefully Chet can comment, but my guess would be is that it's a
consequence of the parser, and it's simpler to inherit the behavior
whereas removing it specifically for case patterns would require a
deliberate change in the code.
Eric
- Why does case-pattern undergo "process substitution"?, shynur ., 2024/08/23
- Re: Why does case-pattern undergo "process substitution"?,
Eric Pruitt <=
- Re: Why does case-pattern undergo "process substitution"?, shynur ., 2024/08/23
- Re: Why does case-pattern undergo "process substitution"?, Lawrence Velázquez, 2024/08/23
- Re: Why does case-pattern undergo "process substitution"?, shynur ., 2024/08/24
- Re: Why does case-pattern undergo "process substitution"?, Eric Pruitt, 2024/08/24
- Re: Why does case-pattern undergo "process substitution"?, Lawrence Velázquez, 2024/08/24
- Re: Why does case-pattern undergo "process substitution"?, Eric Pruitt, 2024/08/24
- Re: Why does case-pattern undergo "process substitution"?, Chet Ramey, 2024/08/26
- Re: Why does case-pattern undergo "process substitution"?, Chet Ramey, 2024/08/26