Re: is the name of the file being interpreted available?

[Ed Morton]

Thanks but I'm looking for the name of the file that contains the awk 
SCRIPT, not the name of the input file that the awk script is reading. 
In your example I'd expect that string to be "-" or "".

    Ed.

On 6/19/2022 10:46 AM, Antonio Giovanni Colombo wrote:
> Hi,
>
> As soon as you start actually processing a file (i.e. AFTER "BEGIN" 
> time), you have the FILENAME variable that holds the name of the file 
> currently being processed.
>
> C:\>echo ciao|gawk " NR==1 { print FILENAME } "
> -
> C:\>gawk " NR==1 { print FILENAME } " alldirs.txt
> alldirs.txt
> C:\>
>
> If you process more than one file, FILENAME will change at each new file.
>
> Hope it helps, Antonio
>
>
> Il giorno dom 19 giu 2022 alle ore 17:28 Ed Morton 
> <mortoneccc@comcast.net> ha scritto:
>
>     I just realised that while shell has $0 to hold the name of the file
>     containing the script being interpreted, I don't know if that same
>     information is available in any builtin variable in awk. Obviously I
>     could write:
>
>          awk -v script='/foo/bar/script.awk' -f '/foo/bar/script.awk'
>     input
>
>     or similar but is there any way to get that '/foo/bar/script.awk'
>     info
>     inside the awk script without any manual intervention so I can
>     just write:
>
>          BEGIN { "we are running", foo }
>
>     for some value of `foo` inside the script to output:
>
>          we are running /foo/bar/script.awk
>
>     Regards,
>
>          Ed.
>
>
>
> --
>  /||\    | Antonio Colombo
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>  / ()  \  | antonio@geekcorp.com
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