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Re: difference between setq and setq-local
From: |
Emanuel Berg |
Subject: |
Re: difference between setq and setq-local |
Date: |
Mon, 27 Sep 2021 05:26:28 +0200 |
User-agent: |
Gnus/5.13 (Gnus v5.13) Emacs/28.0.50 (gnu/linux) |
Pankaj Jangid wrote:
> There are three variants of setq; namely - setq, setq-local,
> setq-default. Meaning of setq-local and setq-default is
> clear from the docstring. i.e. changes made by setq-local
> are not visible outside the current buffer. And changes made
> by setq-default are visible in all the buffers in which the
> value is not set (overridden).
>
> What about plain setq? My assumption is that these changes
> are visible in all the buffers if not overridden by
> setq-local. In this case setq acts like setq-default. Or is
> it the opposite? i.e. setq overrides setq-default valuep; in
> which case it acts like setq-local [...]
Stop it, you are making my head spin :)
I'm not 100% but the way I understood it ...
`setq-local' makes the variable buffer-local, after that
`setq' sets the buffer-local variable while `setq-default'
sets the global value, which is used if the value
isn't set somewhere where/when it's used ...
If there isn't a buffer-local variable setq and setq-default
should be equivalent, i.e. they refer to the global variable.
Some variables as you know automatically gets buffer-local
when set, the help says so often enough for everybody to see
it. So there OTOH setq-local and setq are equivalent while
setq-default still does the same thing.
So setq-local always does the same thing.
And setq-default always does the same thing as well.
setq tho is the tricky one, it refers to the buffer-local
variable if it exists ... _or_ acts like `setq-local' for some
specific variables ... _or_ acts like setq-default if the
there isn't buffer-local variable and also the variable
doesn't stipulate it wants to be buffer-local soo bad!
--
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