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Re: Bash cannot kill itself?
From: |
Chris F.A. Johnson |
Subject: |
Re: Bash cannot kill itself? |
Date: |
Wed, 30 Jun 2010 00:38:53 -0400 (EDT) |
User-agent: |
Alpine 2.00 (LMD 1167 2008-08-23) |
On Wed, 30 Jun 2010, Clark J. Wang wrote:
> I have a bash script like this:
>
> #!/bin/bash
>
> trap 'echo killed by SIGALRM; exit 1' ALRM
>
> function wait_kill()
> {
> sleep 5
> kill -ALRM $$
> }
>
> wait_kill &
>
> sleep 3600
>
> ### END OF THE SCRIPT ###
>
> It does not work as I expected. The running script was not terminated after
> 5 seconds. So what's wrong here?
$$ refers to the subshell. Try:
trap 'echo killed by SIGALRM; exit 1' ALRM
function wait_kill()
{
sleep 5
kill -ALRM $pid
}
pid=$$
wait_kill &
sleep 3600
--
Chris F.A. Johnson, <http://cfajohnson.com>
Author:
Pro Bash Programming: Scripting the GNU/Linux Shell (2009, Apress)
Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
- Bash cannot kill itself?, Clark J. Wang, 2010/06/30
- Re: Bash cannot kill itself?,
Chris F.A. Johnson <=
- Re: Bash cannot kill itself?, Clark J. Wang, 2010/06/30
- Re: Bash cannot kill itself?, Chris F.A. Johnson, 2010/06/30
- Re: Bash cannot kill itself?, Jan Schampera, 2010/06/30
- Re: Bash cannot kill itself?, Clark J. Wang, 2010/06/30
- Re: Bash cannot kill itself?, Jan Schampera, 2010/06/30
- Re: Bash cannot kill itself?, Clark J. Wang, 2010/06/30
- Re: Bash cannot kill itself?, Chris F.A. Johnson, 2010/06/30
- Re: Bash cannot kill itself?, Pierre Gaston, 2010/06/30
- Re: Bash cannot kill itself?, Pierre Gaston, 2010/06/30
- Re: Bash cannot kill itself?, Clark J. Wang, 2010/06/30