Re: Bash cannot kill itself?

[Jan Schampera]

Clark J. Wang wrote:

> Running a cmd in background (by &) would not create subshell. Simple
> testing:
>
> #!/bin/bash
>
> function foo()
> {
>     echo $$
> }
>
> echo $$
> foo &
>
> ### END OF SCRIPT ###
>
> The 2 $$s output the same.

This doesn't mean that it doesn't create a subshell. It creates one, 
since it can't replace your foreground process.

It just shows that $$ does what it should do, it reports the relevant 
PID of the parent ("main") shell you use. As far as I can see, this 
applies to all kinds of subshells like
- explicit ones (...)
- pipeline components
- command substitution
- process substitution
- async shells (like above, running your function)
- ...

J.