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Re: Setting PATH from withing make for $(shell) ?

From: Paul D. Smith
Subject: Re: Setting PATH from withing make for $(shell) ?
Date: Fri, 16 Jun 2006 10:39:10 -0400

%% Cesar Crusius <address@hidden> writes:

  cc> Here's my problem: I'm trying to set up a build system where all
  cc> the executables necessary to build something are in the repository
  cc> itself. So I want the build to fail if it requires any executable
  cc> not in the repository.  The obvious thing to do was


  cc> but that doesn't work as it doesn't set the environment
  cc> variable.

It will, for normal rules.

  cc> For example, if after that I do

  cc> $(warning $(shell which gcc))

  cc> I still get /usr/bin/gcc.

That's because make variables are not exported to the $(shell ...)
function.  This is a bug, but a known bug.  The reason it's not done is
that you can get an infinite recursion situation this way.  That should
be fixed but isn't yet.

If you do this:


    all: ; @echo '$$PATH'

you'll see that the commands in rules _DO_ have the modified value.

 Paul D. Smith <address@hidden>          Find some GNU make tips at:            
 "Please remain calm...I may be mad, but I am a professional." --Mad Scientist

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