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Re: [PATCH] Completion_heads_engraver broken?

From: Michael Käppler
Subject: Re: [PATCH] Completion_heads_engraver broken?
Date: Fri, 27 Feb 2009 17:13:13 +0100
User-agent: Thunderbird (X11/20071114)

moment I can't imagine cases where this could happen.

Can't happen, AFAICT: by the definition of k, k >= -intlog2(p) and so
-k <= intlog2(p) <= log2(p). Therefore 2^{-k} <= p and so (p >> -k) ==
p*2^k >= 1. That is, you never shift everything away.
Ok, so what's the next step now?

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