Re: [bug-gawk] On uninitialized variables

[M]

1. OK.

2. What does it mean "groups together"? They all have different types: 
"number", string" and "regexp" accordingly.

_______________

Yours respectfully,
Mark Krauze

14.05.2019, 14:26, "address@hidden" <address@hidden>:
> M <address@hidden> wrote:
>
>>  After rereading the manual and having some tests, I finally found the 
>> answer to my first question. There's no trouble.
>>  Two questions are still actual. I'll formulate them here.
>>
>>  1. According to the manual (9.1.7 Getting Type Information):
>>
>>  "unassigned - x is a scalar variable that has not been assigned a value 
>> yet."
>>
>>  "And in fact, due to the way gawk works,
>>  if you pass the name of a variable that has not been previously used to 
>> isarray(),
>>  gawk ends up turning it into a scalar."
>>
>>  But the result of "typeof" function after passing a variable to isarray() 
>> is:
>>
>>  $ gawk 'BEGIN { if (! isarray(x)) { print typeof(x) } }'
>>  untyped
>>
>>  Not "unassigned". Why? Is it a bug?
>
> A bug in the manual. I will tend to it.
>
>>  2. The last sentence of the section "9.1.7 Getting Type Information" is:
>>
>>  "The typeof() function is general; it allows you to determine
>>  if a variable or function parameter is a scalar, an array, or a strongly 
>> typed regexp."
>>
>>  A strongly typed regexp is a sort of scalar, isn't it?
>
> In the sense that it's not an array, yes.
>
>>  I don't understand why it is mentioned separately in this sentence.
>
> Because gawk groups 42 and "forty-two" together as scalars,
> distinguished from @/42/.
>
> HTH,
>
> Arnold