Re: [bug-gawk] On uninitialized variables

[arnold]

M <address@hidden> wrote:

> 1. OK.
>
> 2. What does it mean "groups together"? They all have different types:
> "number", string" and "regexp" accordingly.

My bad. (I'm too tired to be doing this...)

> _______________
>
> Yours respectfully,
> Mark Krauze
>
> 14.05.2019, 14:26, "address@hidden" <address@hidden>:
> > M <address@hidden> wrote:
> >
> >>  After rereading the manual and having some tests, I finally found the 
> >> answer to my first question. There's no trouble.
> >>  Two questions are still actual. I'll formulate them here.
> >>
> >>  1. According to the manual (9.1.7 Getting Type Information):
> >>
> >>  "unassigned - x is a scalar variable that has not been assigned a value 
> >> yet."
> >>
> >>  "And in fact, due to the way gawk works,
> >>  if you pass the name of a variable that has not been previously used to 
> >> isarray(),
> >>  gawk ends up turning it into a scalar."
> >>
> >>  But the result of "typeof" function after passing a variable to isarray() 
> >> is:
> >>
> >>  $ gawk 'BEGIN { if (! isarray(x)) { print typeof(x) } }'
> >>  untyped
> >>
> >>  Not "unassigned". Why? Is it a bug?
> >
> > A bug in the manual. I will tend to it.
> >
> >>  2. The last sentence of the section "9.1.7 Getting Type Information" is:
> >>
> >>  "The typeof() function is general; it allows you to determine
> >>  if a variable or function parameter is a scalar, an array, or a strongly 
> >> typed regexp."
> >>
> >>  A strongly typed regexp is a sort of scalar, isn't it?
> >
> > In the sense that it's not an array, yes.
> >
> >>  I don't understand why it is mentioned separately in this sentence.
> >
> > Because gawk groups 42 and "forty-two" together as scalars,
> > distinguished from @/42/.
> >
> > HTH,
> >
> > Arnold