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Re: Converting Outlines to postscript Vector

From: Just van Rossum
Subject: Re: Converting Outlines to postscript Vector
Date: Mon, 28 Feb 2000 18:21:52 +0100

At 4:59 PM +0000 28-02-2000, Satpal Chander wrote:
>   Has anyone tried doing the above from the outline structure as returned
>I have found a page
>It does give a good definition there of howto do it but I'm new to fonts/
>beziers /postscript and the like.
>Can anyone tell me if I can/should get at the curve data directly of through
>api, I'm using 1.3.1.
>Also if the cruve data split into segements or is it just one long curve.

I'm not 100% sure, but it seems FT1.x doesn't have the decompose outline
API like FT2 has, so I guess you'll have to walk trhough the outline object
yourself. Even so, it should be fairly straightforward, though:

- There are on-curve and off-curve points in TT (and therefore in FT1.x)
- Between any two consecutive off-curve points there is an implied on-curve
point (exactly in the middle between them).
- A quadratic segment (onCurve, offCurve, onCurve) can be converted to
cubic beziers (as used by PS) like so:
   let (from, control, to) be the three points making up de quadratic curve
   you need to convert these three points to four points for cubics: (from,
control1, control2, to)
       control1 = from + (control - from) * 2.0/3.0
       control2 = to + (control - to) * 2.0/3.0
   from and to remain the same.

Hope this helps,


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