whats wrong with (( a = 8 , a > 4 && a -= 2 || a-- )) , bash: ((: a = 8 , a > 4 && a -= 2 || a-- : attempted assignment to non-variable (error token is "-= 2 || a-- ")

[alex xmb ratchev]

i remember doing && (( code
maybe i didnt '=' in action there

(( a = 8 , a > 4 && a -= 2 || a-- ))

bash: ((: a = 8 , a > 4 && a -= 2 || a-- : attempted assignment to
non-variable (error token is "-= 2 || a-- ")


(( a = 8 , a > 4 && a-- && a-- || a-- ))

works
a=6

..
i suppose this is a (( lex bug where u didnt include || && in op for =

is it ? :))

greets