Re: whats wrong with (( a = 8 , a > 4 && a -= 2 || a-- )) , bash: ((: a = 8 , a > 4 && a -= 2 || a-- : attempted assignment to non-variable (error token is "-= 2 || a-- ")

[alex xmb ratchev]

or one small deeper parsing bug

~ $ (( a = 8 , a > 4 && a -= 2 ))
bash: ((: a = 8 , a > 4 && a -= 2 : attempted assignment to non-variable
(error token is "-= 2 ")

i can only agree to enable such basic functionment

greets ..

On Thu, Mar 23, 2023, 11:32 alex xmb ratchev <fxmbsw7@gmail.com> wrote:

> i remember doing && (( code
> maybe i didnt '=' in action there
>
> (( a = 8 , a > 4 && a -= 2 || a-- ))
>
> bash: ((: a = 8 , a > 4 && a -= 2 || a-- : attempted assignment to
> non-variable (error token is "-= 2 || a-- ")
>
>
> (( a = 8 , a > 4 && a-- && a-- || a-- ))
>
> works
> a=6
>
> ..
> i suppose this is a (( lex bug where u didnt include || && in op for =
>
> is it ? :))
>
> greets
>