Re: How do I pass a variable defined in a wrapping let, to a lambda?

[Emanuel Berg]

>> Darn -- I thought I understood lexical-binding
>
> Same :(

With static/lexical scope a function within a `let' is
a closure:

(let ((f 2))
  (defun two ()
    f) )
(two) ; 2

But with dynamic/special scope it isn't:

(let ((f 1))
  (defun one ()
    f) )
(one) ; Symbol’s value as variable is void: f

Same with lambdas - they are anonymous functions.

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