Re: Broken beams' slopes

[Carl Sorensen]

On 8/27/11 7:21 AM, "David Kastrup" <address@hidden> wrote:

> Janek Warchoł <address@hidden> writes:
> 
>> I wonder if this solution would yield good results: keep beam slope
>> before and after break identical (except for some beam quanting,
>> perhaps, but that's less than 0.3 ss), but modify stem lengths: make
>> them as long as they would be if there were no beam on the other side
>> of the break.
> 
> I would expect this to yield mostly reasonably results.  I'd also keep
> beam orientation.  But it might make sense to dole out a bit of spring
> force (just decidedly less than infinite) for making the vertical beam
> positions at the break match.


It would seem that this algorithm would fail for  a simple broken beam

a8[ b \break c f]


Or am I missing something?

Thanks,

Carl