Re: [Fab-user] Catching errors in local calls

[David]

Hi Jeff,

On 09/24/2010 10:22 PM, Jeff Forcier wrote:
> Hi David,
>
> On Fri, Sep 24, 2010 at 1:33 AM, David<address@hidden>  wrote:
>
> > I am using fabric for some simple test deployment scripts, and I have
> > encountered a slightly annoying behavior when local(some_cmd) fails. In that
> > case, the output of local is not displayed, making debugging the issue a bit
> > difficult.
>
> I'm not sure what your exact code structure is (it's usually helpful
> to include at least a small snippet when posting ;)) but if you're not
> specifying capture=False, local() captures the output by default,
> instead of displaying it:

My issue is not capturing the output, my issue is to show the output at 
all when there is a failure. Here is a somewhat contrived example

import random
from fabric.api import local

def foo():
    cmd = "ls"
    if random.randint(0, 1) == 0:
        cmd += "s"
    local(cmd)

The command will randomly  fail. At that point, I don't see a way to 
show the output, as a failure in local abort the whole script. I do not 
want to see the output when the command succeeds.

cheers,

David