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## Re: [igraph] a problem with simplify()

**From**: |
Gábor Csárdi |

**Subject**: |
Re: [igraph] a problem with simplify() |

**Date**: |
Thu, 21 Oct 2010 19:14:07 +0200 |

Just for the records, this version works with both kind of indexing:
delete.edges(g, E(g)[is.loop(g)])
Gabor
On Thu, Oct 21, 2010 at 7:06 PM, Tamas Nepusz <address@hidden> wrote:
>*> Definitely, because your code does not take into account that edges are *
>*> reindexed after every deletion. I'd go for delete.edges(g, seq(0, *
>*> ecount(g)-1)[is.loop(g)])*
>* Or, even better: delete.edges(g, which(is.loop(g))-1) if your igraph version *
>* uses 0-based indexing. Note that the R interface of igraph 0.6 has recently *
>* switched to 1-based indexing, so if you installed igraph 0.6 in the last few *
>* days, you don't have to subtract 1.*
>
>* --*
>* T.*
>
>
>* _______________________________________________*
>* igraph-help mailing list*
>* address@hidden*
>* http://lists.nongnu.org/mailman/listinfo/igraph-help*
>
--
Gabor Csardi <address@hidden> UNIL DGM

**[igraph] a problem with simplify()**, *Simone Gabbriellini*, `2010/10/21`
**Re: [igraph] a problem with simplify()**, *Gábor Csárdi*, `2010/10/21`
**Re: [igraph] a problem with simplify()**, *Simone Gabbriellini*, `2010/10/21`
**Re: [igraph] a problem with simplify()**, *Tamas Nepusz*, `2010/10/21`
**Re: [igraph] a problem with simplify()**, *Tamas Nepusz*, `2010/10/21`
**Re: [igraph] a problem with simplify()**,
*Gábor Csárdi* **<=**
**Re: [igraph] a problem with simplify()**, *Simone Gabbriellini*, `2010/10/21`
**Re: [igraph] a problem with simplify()**, *Gábor Csárdi*, `2010/10/21`
**Re: [igraph] a problem with simplify()**, *Simone Gabbriellini*, `2010/10/21`